Spiral Star-Number Hybrid
This program prints a spiral pattern alternating stars and numbers.
Problem Statement
Write a Java program that prints a 5x5 spiral where odd positions are stars and even positions are numbers.
Source Code
| 1 | public class SpiralStarNumberHybrid { |
| 2 | public static void main(String[] args) { |
| 3 | int n = 5; |
| 4 | String[][] arr = new String[n][n]; |
| 5 | int top=0, left=0, bottom=n-1, right=n-1, num=1; |
| 6 | while(top<=bottom && left<=right) { |
| 7 | for(int i=left; i<=right; i++) arr[top][i]=(num%2==0)?String.valueOf(num++):"*"; |
| 8 | top++; |
| 9 | for(int i=top; i<=bottom; i++) arr[i][right]=(num%2==0)?String.valueOf(num++):"*"; |
| 10 | right--; |
| 11 | for(int i=right; i>=left; i--) arr[bottom][i]=(num%2==0)?String.valueOf(num++):"*"; |
| 12 | bottom--; |
| 13 | for(int i=bottom; i>=top; i--) arr[i][left]=(num%2==0)?String.valueOf(num++):"*"; |
| 14 | left++; |
| 15 | } |
| 16 | for(int i=0; i<n; i++) { |
| 17 | for(int j=0; j<n; j++) System.out.print(arr[i][j] + "\t"); |
| 18 | System.out.println(); |
| 19 | } |
| 20 | } |
| 21 | } |
Program Output
* 2 * 4 * * 10 12 14 6 * 18 * 16 8 * 20 22 24 10 * * * * *
Explanation
The spiral logic fills positions sequentially, and the condition (num%2==0) decides whether a position holds a number or a star, so the spiral alternates between symbols based on parity of the running count.