Check Leap Year
This program checks if a year is a leap year using multiple conditions.
Problem Statement
Write a Java program that checks if a year is a leap year.
Source Code
| 1 | public class LeapYear { |
| 2 | public static void main(String[] args) { |
| 3 | int year = 2024; |
| 4 | if((year % 400 == 0) || ((year % 4 == 0) && (year % 100 != 0))) { |
| 5 | System.out.println(year + " is a leap year - Eduinq"); |
| 6 | } else { |
| 7 | System.out.println(year + " is not a leap year - Eduinq"); |
| 8 | } |
| 9 | } |
| 10 | } |
Program Output
2024 is a leap year - Eduinq
Explanation
Leap year rules are: divisible by 400 leads to a leap year; divisible by 4 but not by 100 also leads to a leap year; otherwise it is not. The program uses logical OR and AND operators to combine these conditions. This ensures accuracy across centuries. For example, 2000 is leap (divisible by 400), 1900 is not (divisible by 100 but not 400), and 2024 is leap (divisible by 4 but not 100). Demonstrates multiple condition checks using logical operators.